Wednesday 30 August 2017
An object is launched at a speed of 25.5 m/s from the top of a tall tower. The height y of the object as a function of the time t elapsed from launch is y(t) = ?4.9t2 + 19.32t + 40, where y is in meters and t is in seconds
An object is launched at a speed of 25.5 m/s from the top of a tall tower. The height y of the object as a function of the time t elapsed from launch is y(t) = ?4.9t2 + 19.32t + 40, where y is in meters and t is in seconds. (a) Determine the height H of the tower. (b) Determine the launch angle. ° (c) Determine the horizontal distance traveled by the object before it hits the ground.
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment
Note: only a member of this blog may post a comment.